xcos y-y =cosxy by implicit differentiation pls help!!
ok tell me where are you stuck in doing this question?
i dont have no idea in solving that...its our assignment and it was not been discussed
ok i suggest you differentiate both sides and bring y' to one side
@jayshane We have to differentiate both sides. Hmm... shall we differentiate term by term? I think it would be easier for you to understand..
keep in mind \[\large \bf \text{differential of sum =sum of differentials }\]
example equation pls!!!
Example: Differentiate a sinb with respect to a \[\frac{d}{da}asinb=sinb\frac{d}{da}a + a\frac{d}{da}sinb =sinb + a(cosb)(b')\]
-sin xyy`=-sin xyy` ?
For cosxy \[\frac{d}{dx}cos(xy) = \frac{d}{du}cos(u) \times \frac{d}{dx}(xy)\]u= xy\[=-sinu \times (y\frac{d}{dx}x +x\frac{d}{dx}x)\]\[=...\]
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