gen chem 1: a 2.5600 gram sample of a sulfur-containing compound is analyzed by precipitating the sulfur as BaSO4. If 1.1756 g of BaSO4 are obtained, what is the percentage of sulfur in the sample?

Question

anonymous · Answer

my work: 1.1756 g BaSO4  x 1mol BaSO4/233.39 g BaSO4 x 1 mol S/1mol BaSO4 x 32.065 g s/1mol s x 1/2.5600 g sample x 100% = 6.3091%

Is this correct?

anonymous · Answer

n(BaSO4) = 1.1756/233 = 0.005 mol
m(S in BaSO4) = 0.005*32= 0.16 g (this sulfur is the sulfur in the sample as well)
w(S in the sample) = 0.16/5600 * 100% = 0.0029%

anonymous · Answer

We it the same way except the sample is 2.5600g instead of 5600.

anonymous · Answer

Thanks