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Chemistry 9 Online
OpenStudy (anonymous):

Find the [acid] / [conjugate base] ratio that will yield the specified pH: a. [HC2H3O2] / [C2H302-] for pH 4.50 b. [HNO2] / [NO2-] for pH 3.41 c. [NH4+] / [NH3] for pH 9.50

OpenStudy (anonymous):

Another is 0.16 of HZ is 1.2% dissociated. Calculate the pH of the solution and Ka.

OpenStudy (aaronq):

use the henderson hassle back equation \[pH = pKa + \log \frac{ [A-]}{[HA] }\]

OpenStudy (aaronq):

or i guess since they're asking for the ratio of acid/conjugate base, invert the last part: \[pH=pKa-\log \frac{ [HA] }{ [A ^{-}] }\]

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