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Mathematics 9 Online
OpenStudy (dumbsearch2):

Graph the solution set of the system of inequalities: x < 2 -x + y < 2

OpenStudy (dumbsearch2):

Which one should I choose?

Parth (parthkohli):

Let's take the second inequality and solve for \(x\) :-)

OpenStudy (dumbsearch2):

@ParthKohli how? like what?

Parth (parthkohli):

Actually, you could just solve for \(y\) like this: \(y < 2 + x\).

OpenStudy (dumbsearch2):

like which graph? ;)

Parth (parthkohli):

And \(x\) is less than \(2\), right?

OpenStudy (dumbsearch2):

i think..

Parth (parthkohli):

I can't really tell you the answer, I'd lead you to it!

OpenStudy (dumbsearch2):

ok then! :)

Parth (parthkohli):

So, \(x\) can't be more than \(2\).|dw:1358655822776:dw| We start by this line.

Parth (parthkohli):

Also, \(y < 2 + x\). If we take \(x =1\), then \(y < 2 + 1\) right?

OpenStudy (dumbsearch2):

right!

OpenStudy (dumbsearch2):

:)

Parth (parthkohli):

Yup, so we can kinda "shade" all the \(y\)'s less than \(3\) where \(x =1\).|dw:1358655945754:dw|

Parth (parthkohli):

And then we can take \(x =0\), so \(y < 0 + 2\) right?

OpenStudy (dumbsearch2):

yes

Parth (parthkohli):

So we can "shade" all the \(y\)'s less than \(2\) at \(x = 0\). OK?|dw:1358656076242:dw|

OpenStudy (dumbsearch2):

k

Parth (parthkohli):

And finally, join both blocks and continue that|dw:1358656133606:dw|

OpenStudy (dumbsearch2):

Alright!

Parth (parthkohli):

Do you see something similar in the choices?

OpenStudy (dumbsearch2):

So like this?

Parth (parthkohli):

Yes.

OpenStudy (dumbsearch2):

That's the answer? :)

Parth (parthkohli):

Yeah!

OpenStudy (dumbsearch2):

THANKS SO MUCH! :-)

Parth (parthkohli):

:-D

OpenStudy (dumbsearch2):

He you're BRILLIENT!!!!!!!! GENIUS!

Parth (parthkohli):

LOLZ

Parth (parthkohli):

That is the worst joke ever!

OpenStudy (dumbsearch2):

Not a joke! :|

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