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OpenStudy (anonymous):
A student claims that if one of the interior angles of a parallelogram is 30, then it cannot be inscribed in a circle. Do you agree with him? Explain.
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OpenStudy (ash2326):
We start with assuming that the parallelogram is inscribed in a circle.
|dw:1358656384414:dw|
Assume this to be a parallelogram ABCD
OpenStudy (anonymous):
yes
OpenStudy (ash2326):
|dw:1358656432945:dw|
Now angle A= angle C
OpenStudy (anonymous):
why they are equal?
OpenStudy (ash2326):
A= C ( opposite angles of a parallelogram are equal)
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OpenStudy (anonymous):
isn't that A+C=180?
OpenStudy (anonymous):
ohhh. parallelogram .... nothing then
continue please
OpenStudy (ash2326):
For a cyclic quadrilateral opposite angles sum should be 180, we have to satisfy this property also
OpenStudy (anonymous):
ok...
OpenStudy (ash2326):
so we have to have
\[A=C=90\]
this makes the parallelogram a rectangle, so any parallelogram which is inscribed in a circle is a rectangle
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OpenStudy (anonymous):
and then>
OpenStudy (ash2326):
Therefore a parallelogram with one angle 30 can't be inscribed
OpenStudy (anonymous):
ok...how about one angle is 150 degrees? the opp. angle can be 30
OpenStudy (ash2326):
But opposite angles of a parallelogram are equal,
OpenStudy (anonymous):
ohhh yes..
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OpenStudy (anonymous):
thank you so much
OpenStudy (ash2326):
Welcome :D
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