Question

what is the value of x in:
-x^3+5x^2-2x-4=0

Answer 1

Either sign is incorrect or calculator wont work for this question, means you have to apply other methods

Answer 2

In whatever your lecture teaches you

Answer 3

hahaha really thanks .. will may be i got it wrong from the start
the question is find the critical point of :
y=(x^3-2x^2-x+2)over (x-2)

Answer 4

\[y=\frac{ x ^{3}-2x ^{2} -x+2}{x-2}\]

Answer 5

Simplifying
y = (x3 + -2x2 + -1x + 2)

Reorder the terms:
y = (2 + -1x + -2x2 + x3)

Remove parenthesis around (2 + -1x + -2x2 + x3)
y = 2 + -1x + -2x2 + x3

Solving
y = 2 + -1x + -2x2 + x3

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 2 + -1x + -2x2 + x3

Answer 6

y = 2 + -1x + -2x2 + x3 = [ (2-X) + x^2 (x-2) ] / (x-2)
X= +2 or -2 or 0

Answer 7

thanks