Question

PLEASE HELP !!!
Which two numbers have a percent of increase of approximately 21% ?

Answer 1

Ok you need the difference between the two numbers, then you divide that by the number you started with. So in your case it would be

Hope that helps.

Answer 2

@pooja195 ,Thank you sooo muchh!:p

Answer 3

But what are the 2 numbers,how do i get them???

Answer 4

There are infinitely many pairs of numbers which have a percentage of increase of approximately 21%. There must be more to your problem. Or maybe you are just supposed to provide such a pair.

Answer 5

Well, it just asks the questions and the choices to it..
a. 12 to 19
b. 101 to150
c. 10 to 21
d. 126 to152

Answer 6

@whpalmer4

Answer 7

Okay, which of those pairs has one number that is 21% greater than the other?

Answer 8

If you have two numbers, a and b, the percentage a > b is given by

\[\frac{(a-b)}{b}*100\%\]

So, if a = 3, b = 2, the percentage 3 is greater than 2 is
\[\frac{3-2}{2}*100\% = 50\%\]

Answer 9

If you want to find a number a that is x% larger than a number you have (b),

\[a = (1+\frac{x}{100\%})*b\]
If the number you have is 1000, and you want to find a number 21% greater:
\[a = (1+\frac{21\%}{100\%})*1000=1.21*1000 = 1210\]

Answer 10

So, look at the numbers in your answers: does 1.21* the first number give you the second number for any of them? Be careful, there are some trick answers in there.

Answer 11

@whpalmer4 , So would it be D. , i did the (a-b/bx100%) and i got -26%

Answer 12

Yes, it would be letter D, but I'm not sure I understand how you got -26%

Answer 13

i got a. -7%, b.-49%, c. -5%, d.-25%