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Mathematics 77 Online
OpenStudy (anonymous):

Given the following language definition: L = {w ϵ {a, b}* : x ϵ {a, b}+ (w = axa)} ||| Give a simple English description, two words it contains, and two it does not.

OpenStudy (anonymous):

The words must all begin with 'a' and end with 'a'

OpenStudy (anonymous):

can there be a string with zero length?

OpenStudy (experimentx):

no

OpenStudy (anonymous):

is this because of the plus sign?

OpenStudy (experimentx):

but i don't understand fully what you are trying to say.

OpenStudy (anonymous):

basically looking for strings which would be found in the language as defined in the question

OpenStudy (experimentx):

\[ L = \{ w \in (a,b)^*:x\in (a,b) + (w=a \times a) \}\] how do you interpret this statement?

OpenStudy (anonymous):

There is a language such that w is an element of L containing any combinations of the symbols 'a' and 'b'...

OpenStudy (anonymous):

If X is in L, and contains at least one a and b, X must begin with a and end with a

OpenStudy (anonymous):

this last part means that there cannot be a string with no b's unless if is an empty string

OpenStudy (experimentx):

I have never seen those representation before. I think there is no word in English that begins with 'a' and ends with 'a' and only containing 'a' and 'b'. If a set does not have any elements then it's a null set.

OpenStudy (experimentx):

try searching for few words online http://www.thefreedictionary.com/

OpenStudy (anonymous):

English has nothing to do with it, except that I need to explain the fictional language in English

OpenStudy (experimentx):

isn't this related to sets??

OpenStudy (anonymous):

yes, the words which make up the language will be a set of words, the first being the empty set

OpenStudy (anonymous):

sorry, word with no characters, not the empty set

OpenStudy (experimentx):

then you can have infinite words. begin with 'a' then add up as much as you like, then again end with 'a'.

OpenStudy (anonymous):

is there one exception, meaning the plus sign (one or more)?

OpenStudy (anonymous):

x is an element of words with at least one a and one b if it begins with a and ends with a?

OpenStudy (experimentx):

just get the two word that is contained in X and 2 word not contained in X. eg. aba, ababa <--- these two are contained in X eg. baba, abab <--- these two are not contained in X

OpenStudy (experimentx):

L being superset of X, contains all those 4 elements, but X does not contain those last two elements of L, because of the criteria imposed on X for its members.

OpenStudy (anonymous):

X appears to be a representation of a substring of strings which begin with a and end with a, not a subset of L

OpenStudy (experimentx):

don't you need a word that X does not contain?

OpenStudy (anonymous):

that L does not contain

OpenStudy (experimentx):

a word that is contain in X but not contain in L?

OpenStudy (anonymous):

X is merely a representation of a word within L it appears

OpenStudy (experimentx):

so you need 2 words that L does not contain?

OpenStudy (anonymous):

yes

OpenStudy (experimentx):

any word containing 'a' and 'b' would be contained in L, either we construct a word from other characters or there is no such word.

OpenStudy (anonymous):

bab would be a word not in L?

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