Question

Find cot θ if csc θ = (square root of 17)/4 and tan θ > 0

Answer 1

you need the third side, which you get by pythagoras
it is \(\sqrt{\sqrt{17}^2-4^2}=\sqrt{17-16}=1\)

Answer 2

So, the answer is 1?? Because my answer choices are:
sqrt 17
1/4
(sqrt 17)/17
17

thanks for your help btw (: @satellite73

Answer 3

\[\large \csc \theta = \frac{\sqrt {17}}{4} \qquad \rightarrow \qquad \frac{1}{\sin \theta}= \frac{\sqrt {17}}{4} \qquad \rightarrow \qquad \sin \theta=\frac{4}{\sqrt {17}}\]

While Sat has the right idea, I think we have the triangle setup incorrectly :)

Answer 4

Finding the missing side as Sat did gives you 1

Answer 5

\[\cot \theta = \frac{adjacent}{opposite}\]

Answer 6

Ohhhh... okay! So, the answer would be 1/4? (:

Answer 7

Yay good job! \c:/

Answer 8

Thank you so much!! :D