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Mathematics 8 Online
OpenStudy (anonymous):

find the volume of the square pyramid shown. Round to the nearest tenth if necessary. 33.3 ft3 400 ft3 1,200 ft3 600 ft3

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

Volume = (Area of the base)*(Height)/3

jimthompson5910 (jim_thompson5910):

It may help to draw a picture |dw:1358719075534:dw|

OpenStudy (anonymous):

so the slant height is more than the height itself?

jimthompson5910 (jim_thompson5910):

That is correct and if h is the height, s is the slant height and b is the base (of one of the triangles), then b^2 + h^2 = s^2

OpenStudy (anonymous):

so if b^2=100 and s^2=169 then h^2 would equal the difference?

jimthompson5910 (jim_thompson5910):

b is actually 5, not 10 b^2 = 25 s^2 = 169 so h^2 = s^2 - b^2 h^2 = 169 - 25 h^2 = 144 h = ??? so you are correct in saying "h^2 would equal the difference"

jimthompson5910 (jim_thompson5910):

|dw:1358719925361:dw|

OpenStudy (anonymous):

so h equals 12?

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

now use the formula Volume = (Area of the base)*(Height)/3

jimthompson5910 (jim_thompson5910):

what did you get for the area of the base

OpenStudy (anonymous):

40

jimthompson5910 (jim_thompson5910):

Base is a square |dw:1358720139519:dw|

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