Ok i have a graph with an amplitude of A which is 6. And the period is pi. It is a -sin graph. My guess for the equation of this graph was -6sin2x i tried this with parenthises and without no luck. Is there something else it could be or is this simply the wrong equation? Further description of graph: starts at orgin goes down and like a sin curve goes to -A then back up to A and back to zero. The period of this is pi.
Can you post the actual graph?
Nope i can't pull up the graph Swear what i say is right i've had two people look at it and screw up too.
So your graph looks like this |dw:1358731657265:dw|
Exactly i have no clue how you did that but yup thats it
Thanks fot the help
I used the draw feature
The answer is y = -6*sin(2x), but you can easily do phase shifts to get equivalent answers. However, y = -6*sin(2x) is the most basic one.
So there might be a typo somewhere
could it be that the distance from peak to valley is 6 units? if so, then that would make the amplitude to be 3
Thats what i put in but nothing. If you can think of anything else it would be appreciated but you helped the most for sure
So you also tried y = -3*sin(2x) and that didn't work?
I'll try that too thanks
let me know how it goes
No luck locked out but i had no shot anyway thanks
np
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