Acceleration of a particle is increasing linearly with time. It’s acceleration is 10m/s2 at t=0 and 20 m/s2 at t=5s. Also, it’s speed is 5 m/s at t=0 and it’s position is x= -100m at t=0.Find at time t it’s acceleration, velocity and position.

Question

anonymous · Answer

would this involve solving differential equations?

anonymous · Answer

yup..i think so

anonymous · Answer

then we got$$da /dt = 4m/s^3 $$

anonymous · Answer

$$so ......d^3x/dt^3 = 4.. $$

solve this and you ll get the equation for displacement

anonymous · Answer

what's the ans u got ??

anonymous · Answer

can't you solve that D.E ?

shubhamsrg · Answer

We are given
a= kt + c

a=10 at t=0 and a=20 at t=5

using this, we can find out k and c.

now a = dv/dt

=> dv = ktdt + cdt

integrate both sides
you'll get something like

v = kt^2 /2 + ct + m

v=5 at t=0,
so you can find out m

now v=ds/dt

same way find out s=f(t).

Hope this helps ?

anonymous · Answer

thanks :D it really did help :)

anonymous · Answer

:P..

vincent-lyon.fr · Answer

By the way, "its" is not "it's" !

anonymous · Answer

oh great ..thanks for correcting it...