Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

y + 2 = 1/3(x – 5); (–4, 3) (1 point)

Answer 1

***Or at least help me please (:

Answer 2

need to be able to recognize the slope of the given line. that will be helpful to determine the perp slope

Answer 3

Thank you

Answer 4

the general line form you have given is:

\[y-y_o=m(x-x_o)\]

where m is the slope

Answer 5

a perp line has the negative flip of the given m; can you define the "m" part for me?

Answer 6

1/3? I'm really not all that good at this

Answer 7

you are correct :)

the negative flip of that is what we want: 1/3 flips and negates to -3

Answer 8

so we have at least:
\[y-y_o=-3(x-x_o)\]

the x0 and yo parts are the given point (-4,3)

so they just fill in

can you show me the finished results?

Answer 9

y - -4 = -3(x -3)
Sorry if I'm way off

Answer 10

you did that perfectly; and to clean it up, remember that 2 negatives is a positive: -- = +

y + 4 = -3(x-3)

good job

Answer 11

wait ... almost perfectly

Answer 12

you got the x and y inthe wrong spots, and i did too

Answer 13

xo = -4, yo= 3

y -3 = -3(x -- 4)

y -3 = -3(x + 4)

thats better

Answer 14

Oh okay thank you so much

Answer 15

We start a letter with "yo" and end it with "xo" :-)

Answer 16

if you are satisfied with the results of this question, go ahead and close it so that you can ask a new question. Otherwise people wont really know if you are asking a new one, or replying to this old one

Answer 17

How do I close it? sorry

Answer 18

Oh wait I figured it out. Thank you!

Answer 19

over on the left side of the screen it says bump close; just hit close

Answer 20

:)

Answer 21

good luck ;)