in a reversible reaction at equilibrium A(g)=2B(g) if A and B changes its state from gas to liquid what will be the effect on equilibrium?
Are you familiar with Le Châtliers principle?
Yeah!
Where do you think the equilibrium shifts. I'm confident that you are able to answer this question. Try it.
ok now basically the changing of state implies that the volume changes appreciably ..but how to attack now? thru' concentration or pressure ?
but once the gas changes to liquid i cannot apply that, right?
Yep
then ?
ok can i say like this ? since the volume decreases and mass remains constant the concentration of the reactant and product increases..now the system would try to undo the effect of increament in concentration ..so the equillibrium shifts in the direction where concentration is lesser..since volume is same for both the gas the one with the lesser number of moles will have lower concentration..that is A so the equilibrium shifts towards left?
That makes sense. Remember that concentration is M/V so if you change the volume, then the concentration changes to the left. Yes.
ok.thanks so much!
Don't thank me :) you did came up with this on your own! Good job!
Just a tiny push. Best of luck, Cheers.
:)
Join our real-time social learning platform and learn together with your friends!