Find all zeros of g(x)=2x^3+x^2-22x+24 given that x=2 is a zero
Can I use synthetic division here?
factor as \((x-2)\times (\text{something})\) and then use the quadratic formula to find the zeros of the "something" you can find it by dividing using synthetic division
yes, use synthetic division is easiest method hardest method is long division medium method is thinking about what it has to be
Okay. How about this..."Find all factors of x^3-x^2-5x-3 given that (x+1) is a factor"
Can I use synthetic division there too?
yes
So would the answer be in standard form?
\[x^3-x^2-5x-3 =(x+1)(whatever)\]
actually for this one thinking would not be too hard
\[x^3-x^2-5x-3 =(x+1)(x^2+bx-3)\] you only need to find the \(b\) because the first and last term are obvious
since \(-3x+bx=-5x\) that tells you \(b=-2\) giving \[x^3-x^2-5x-3 =(x+1)(x^2-2x-3)\]
but you can use synthetic division if you find it easier
But it says I have to find the factors..so once I finish with the synthetic division and I have my answer in standard form, do I just factor out whatever I got from the synthetic division?
So I got this after doing synthetic x^2-2x-3 So would I factor that?
yeah that one should be easy right?
Yeah, sorry about my stupidity. I have a test tomorrow and I'm scrambling to learn this pellet
pellet? I typed in sh**
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