Question

The coefficient of friction opposing the sliding of a 5.00 kg rubber chicken across the top of a table is 0.408. How hard must you pull to make the rubber chicken slide with an acceleration of 2.00 m/s2?

Answer 1

First, calculate the frictional force:\[F_f=U_kmg=(0.408)(5.00kg)(9.8m/s^2)=19.992N\]Next determine the force required to move the object at 2.00m/s^2:\[F=ma=(5.00kg)(2.00m/s^2)\]The answer will be the sum of those forces.