use the method of substitution to solve the system of linear equations. 2x-y=3 9x-4y=15 the solutions is ? (type an ordered pair)
take the 1st equation and rewrite it y = 2x - 3 substitute it into the 2nd equation 9x - 4(2x -3) = 15 all you need to do is distribute, collect like terms and solve for x
its confusing to me im not understanding it at all.
multiply equation 1 by 9, and equation 2 by 2, so as to get : \[ 18x - 9y = 27\] \[18x-8y = 30\] subtract 2 from 1 so as to get \[-y = -3 \] so the answer is y =3, and x = (3 + y) /2 = 3, answer is (3,3)
oh well no need to explain...@kjos has given you an answer... good luck
the idea behind solving such problems is to eliminate unknowns one by one
the only problem is he has used elimination
you require substitution
thank you i will have to study up more on this type of stuff
i agree. campbell's solution is the right one. i missed the requirement for substiution.
so whats the substitution part
@kjos the aim of the site it to help understanding... not give answers
answer help me see how it is solved
in a weird way, i have not ;-) . Substitution in this case means that we have been given 2 unknowns, x and y. If we can somehow express x in terms of y, or vice versa, we can replace where-ever we see x in terms of this new expression. thus we "substitute" x with this new expression for x. so the substitution method. In this case, we have been given that \[2*x - y =3\] so \[y = 2*x -3\], and then we can "substitute" this whereever we see y e.g. in the second equation
so there is is another pair of numbers?
nope, the answer is right, just that there are at least 2 ways of arriving at the solution. The solution i mentioned in the beginning is called the "elimination method", - what you want is the "substitution method", which is what campbell described and i just described (my 2nd post)..
I got to as far as 9x+-4(-3)+-4(2x)=15
yep, carry on .... right direction. get all the x's together and the non-x's together
ok i think i am somewhat understanding it.
thank you for helping me both of yall.
Join our real-time social learning platform and learn together with your friends!