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A rock is thrown vertically upward with an initial speed of 100 ft/s. At the same instant another rock is thrown vertically downward from the top of a 280 ft cliff with an initial speed of 40 ft/s. Neglecting air friction,
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Lol....wat we have to find here....is it the time when they both Will meet ryt ?
yea the time and position!
so how then we can find the time?
V = Vu - ( -Vd) = 100 + 40 = 140ft/s
V = d/t t = d/t t = 280 / 140 = 2s
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