Given sin A = .43 find angle A in degrees. Round your answer to the nearest hundredth.
inverse the sin and you'll find the answer so sin-1(.43)=25.5degrees
Given tan B = .10 find the angle B in radians. Round your answer to the nearest hundredth
set your calculator to radians and again inverse the trig function and you get 5.71
Given sinB = 11/18 find angle B in degrees. Round your answer to the nearest hundredth.
do you need a calculator? Once again inverse the sin-1(11/18) to find the degrees. 37.67 degrees
ignore my 5.71 answer i don't have a radian calculator.
the one with .10 didnt work the choces are .10 .20 .30 or .05
|dw:1358864915755:dw|Given the following triangle, solve for the missing side.
use pythagoras theorem for that solve it. 5^2+4^=c^2 solving for c you get 6.4
|dw:1358865069808:dw|Given the following triangle, solve for angle Y.
for tan-1(.1) in rads = .0996686 radians. I helped you can you best reponse me?
|dw:1358865157787:dw|Given the following triangle, find angle C
for your last question once again use Pythagoras theorem. 4.6^2=3.5^2+b^2 solving for b you get 2.9849623
i'll help you with this last one then you should open another question.
idk how to use this
for the next one it's a two step solution. My approach is I found the side adjacent to the degree. So 25cos34=20.72 then once again you can use the theorem. And you should arive at 13.97982259 or 14 depening on how you need to round
Join our real-time social learning platform and learn together with your friends!