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Solve. 2/3(p+3)=1/3-P
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get rid of fraction! multiply both sides by 3
\[\frac{2}{3}(p+3)=\frac{1}{3}-p\] \[3\left(\frac{2}{3}(p+3)\right)=3\times \left(\frac{1}{3}-p\right)\] \[2(p+3)=1-3p\]
then proceed as usual \[2p+6=1-3p\]\[5p+6=1\] etc
yay i was doing the process right :)
let's see if i get it right
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Do you have to add 5p to each sides? @satellite73
typo there after \[2p+6=1-3p\] add \(3p\) to both sides gives \[5p+6=1\] now subtact \(6\) from both sides
you want all the \(p\) terms on one side, all numbers on the other you should get \(5p=-5\) then divide by 5
would it be \[\frac{ -5 }{ 5 }\]
Never mind got it's -1
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