What is x? A.2√5 B.3√5 C.6
use pythagorean theorem on larger triangle to get x
using x value solve for y from smaller rt angled triangle using pythagorean theorem again!
That drawing is obviously not made to scale, judging from the segments labeled 4 and 5 :-) You've got two similar triangles. 4:x as x:9 because the corresponding sides must be proportional. From that you can find the value of x.
:)
@AravindG my first instinct was to go the way you suggested, but without a known relationship between x and y, I ran into a roadblock.
i see
Is there something I'm missing that would get past that?
you should recognize that all 3 triangles are similar to each other (whpalmer pointed this out) |dw:1358875592296:dw| in a right triangle, you have angle A and angle B (=90-A) so you can label each angle as either A or B.
|dw:1358875759087:dw| notice y is opposite angle B in the triangle on the right and 5 is opposite angle A in the small triangle on the left, 4 is opposite angle B and y is opposite angle A set up a ratio \[ \frac{y}{5}= \frac{4}{y} \] This is an important idea. y is the geometric mean of the two numbers you can see (cross multiply) that y^2 = 20 now you can find x: use pythagoras
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