Question

A car is speeding up and has an instantaneous velocity of 3.0 m/s in the +x-direction when a stopwatch reads 10.0 s. It has a constant acceleration of 2.5 m/s2 in the +x-direction.
(a) What change in speed occurs between t = 10.0 seconds and t = 13.0 s?
(b) What is the speed when the stopwatch reads 13.0 s?
PLEASE, I NEED HELP WITH THE STEPS...thank you :)

Answer 1

p e n i s

Answer 2

Since acceleration is constant, you can use the following kinematic equation using a time of 13.0s-10.0s=3.0s:\[\Delta V = at\]\[V_f=3.0m/s + (2.5m/s)(3s)=10.5m/s\]That gives the answer to b. The answer to a to should be obvious.

If you have any questions just ask :)

Answer 3

thank you sooooooooooooo much I truly appreciate it! :)))

Answer 4

no problem :)

Answer 5

I really dont want to seem annoying but, i just have one question that no one knw how to help me with, and you seem like you know what you're doing...Im very DESPERATE for help on the following question (i literally spent hours trying to solve it) :

You drop a stone into a deep well and hear it hit the bottom 1.70 s later. This is the time it takes for the stone to fall to the bottom of the well, plus the time it takes for the sound of the stone hitting the bottom to reach you. Sound travels about 343 m/s in air. How deep is the well?

please, only answer if you have time (i hope im not being annoying). thank you tho :))

Answer 6

http://openstudy.com/users/heythere123#/updates/50fdf439e4b00c5a3be5b5f2 this is my link (so i can award you some medals for your answer)

Answer 7

This is a common question that I've answered before...let me find it :)