Question

Help Please ! Explain The Steps ..
Simplify the sum. State any restrictions on the variables.
(x - 2)/(x + 3) + (10x)/(x^2 - 9)

Answer 1

\[\frac{ x - 2 }{ x + 3 } + \frac{ 10x }{ x^2 - 9 }\]

Answer 2

@Hero please help

Answer 3

@campbell_st help !!

Answer 4

@amoodarya

Answer 5

walk me through this please

Answer 6

ok... so you need a common denominator to add fractions

if you factorise the denominator of the 2nd fraction you get

\[\frac{x -2}{x -3} + \frac{10x}{(x - 3)(x +3)}\]

the common denominator is (x -3)(x + 3)

so multiply the numerator and deniminator of the 1st fraction byt (x + 3)\[\frac{(x -2) \times (x + 3)}{(x - 3)\times(x + 3)} + \frac{10x}{(x -3)(x + 3)}\]


if you distribute and collect like terms in the numerator then factorise if possible you'll find there is a common factor that cancels.