Who wants medals! 2x + 3y = 3
3x – 2y = 11

What is the solution to the system?

(–3, 3)

(–1, –7)

(1, –4)

(3, –1)

Question

Who wants medals! 2x + 3y = 3 
3x – 2y = 11 

What is the solution to the system?

 (–3, 3)

 (–1, –7)

 (1, –4)

 (3, –1)

whpalmer4 · Answer

Why don't you multiply the first equation on both sides by 3, and the second equation on both sides by 2, and add them together?  You should find that you now have an equation with only 1 variable, which you can solve.  Use that value in either of the original equations to find the other one.  Then select the correct answer, and I'll give you a medal!

whpalmer4 · Answer

Sorry, multiply the first equation by 2, the second equation by 3...

amoodarya · Answer

then sum of them 

deleted y
so you solve for x

anonymous · Answer

is it x + 3y =6

anonymous · Answer

@whpalmer4

amoodarya · Answer

attachment

whpalmer4 · Answer

No.

$$2x + 3y = 3$$$$3x-2y = 11$$

Multiply the first one by 2, and the second by 3:
$$2*2x + 2*3y = 2*3$$$$3*3x - 3*2y = 3*11$$
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13x                      = 39

solve that for x, then use it to find y.