Question

How would I rearrange the following formula so as to solve for a?
d=1/2(a)(t^2)+ai(t)

Answer 1

Would it be
a=(d-vi(t))/(1/2(t^2)

Answer 2

\[d=\frac{1}{2at^2+ait}\]

Answer 3

Is that the problem?

Answer 4

No, \[d= \frac{ 1 }{ 2 }at ^{2}+v _{i}t\]

Answer 5

1. Subtract v_it from both sides
2. Multiply both sides by 2
3. Divide both sides by t^2

Answer 6

\[(d-vi)/t^2=\frac{ 1 }{2 }a\]

Answer 7

So then we get that ^ ?

Answer 8

An how can we subtract vi if it's attached to t?

Answer 9

\[d-v _{i}t=\frac{1}{2}at^2\]

Answer 10

Oh sorry you said vit

Answer 11

\[2d-2v _{i}t=at^2\]

Answer 12

\[\frac{2d-2v _{i}t}{t^2}=a\]

Answer 13

Thank you!!

Answer 14

yw