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Mathematics 13 Online
OpenStudy (anonymous):

add! medal for the CORRECT answer!

OpenStudy (anonymous):

OpenStudy (anonymous):

11x?

OpenStudy (anonymous):

Can you simplify the first radical by finding the perfect square that fits in it?

OpenStudy (anonymous):

11s isn't an option ):

OpenStudy (anonymous):

@HorseCrazyGirlForever Try not to just post the answer.. try to explain how ya got there

OpenStudy (anonymous):

i believe so

OpenStudy (anonymous):

So what perfect square fits into 18?

OpenStudy (unklerhaukus):

\[\sqrt{18x}+\sqrt{2x}\] \[=\sqrt{9\times2x}+\sqrt{2x}\] \[=\sqrt{9}\times\sqrt{2x}+\sqrt{2x}\] \[=\sqrt{3^2}\times\sqrt{2x}+\sqrt{2x}\] \[=\]

OpenStudy (anonymous):

Geez I don't know if that is correct... :(

OpenStudy (anonymous):

Could I get some help with my question when you guys are done here? I really need to get it done....

OpenStudy (anonymous):

UncleRhaukus, the final answer isn't showing ):

OpenStudy (anonymous):

@UncleRhaukus

OpenStudy (whpalmer4):

You're supposed to figure it out!

OpenStudy (anonymous):

I dont think he wanted it to show, i think he wanted you to do it

OpenStudy (anonymous):

ughhhhhh

OpenStudy (anonymous):

i need to get this overwith, so if anyone can just give me the answer real quick, i'll give them their medal.

OpenStudy (whpalmer4):

Oh, come on, it's easy! What is 3*3? and what number * itself gives you 9?

OpenStudy (unklerhaukus):

\[=\sqrt{3^2}\times\sqrt{2x}+\sqrt{2x}\] simplify this bit \(\sqrt{3^2}\) then combine the like terms

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