What are the steps to solve this problem? Factoring Quadratic Equations.
12(x)^(2)-41(x)+24=0

Question

What are the steps to solve this problem? Factoring Quadratic Equations.
12(x)^(2)-41(x)+24=0

mertsj · Answer

Use the quadratic formula.  a = 12, b = -41, c = 24

anonymous · Answer

Could you work it out for me? I have 12.24=288 . 32 and 9 are common den..

hero · Answer

You don't need the quadratic equation to solve this. You need to factor it

mertsj · Answer

$$x=\frac{41\pm \sqrt{41^2-4(12)(24)}}{2(12)}=\frac{41\pm \sqrt{1681-1152}}{24}$$

mertsj · Answer

Ok.  Now the real brain will help you.  Good bye.

anonymous · Answer

thank you

hero · Answer

12x^2-41x+24=0
12x^2 - 32x - 9x + 24 = 0
4x(3x - 8) - 3(3x - 8) = 0
(3x - 8)(4x - 3) = 0

anonymous · Answer

Thank you Hero. You are my Hero!!! I get it now!!!

hero · Answer

You figure it out by finding two numbers that multiply to get 12*24, yet add to get -41

hero · Answer

mn = 288
m + n = -41

The only two numbers that work are m = -32, n = -9

anonymous · Answer

Yes I had that right. not nothing else. Thanks a lot!!!