can someone help me with these 3 proofs, I have attached the file.. it has to get done by today! and i really appreciate it:) medals rewarded!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
@roberman228
OpenStudy (anonymous):
okay:)
OpenStudy (anonymous):
yea, ive tried google
OpenStudy (anonymous):
@whpalmer4 can you help?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@jim_thompson5910 can you help me with these couple of questions about geometry proofs?
jimthompson5910 (jim_thompson5910):
how far did you get on #2
OpenStudy (anonymous):
um i think i finished that one, not sure let me check
jimthompson5910 (jim_thompson5910):
ok post what you got
OpenStudy (anonymous):
im not so sure how to do it?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
or just write it out here
OpenStudy (anonymous):
like what do you mean?
OpenStudy (anonymous):
# 2 im not sure what to do
OpenStudy (anonymous):
what is the first step i need to do @jim_thompson5910 ?
jimthompson5910 (jim_thompson5910):
well start with what you are given
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so would it be
BCD=EDC
BCD=ECD
OpenStudy (anonymous):
both are given?
jimthompson5910 (jim_thompson5910):
good, start off saying those two sets of angles are congruent because that's given
OpenStudy (anonymous):
so then it would look like this?
BCD=EDC|GIVEN
BCD=ECD|GIVEN
and then now what?
jimthompson5910 (jim_thompson5910):
what segments can you say for sure are congruent
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
uuhmm not so sure.
OpenStudy (anonymous):
i would have to say that BCD and BED are congruent right?
jimthompson5910 (jim_thompson5910):
what segment is between angles BCD and EDC
OpenStudy (anonymous):
is it just one segment?
jimthompson5910 (jim_thompson5910):
yes do you see it?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
CDE?
jimthompson5910 (jim_thompson5910):
segment, not angle
OpenStudy (anonymous):
F?
jimthompson5910 (jim_thompson5910):
that's a point, not a segment
OpenStudy (anonymous):
whats a segment?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
there's the figure
|dw:1358891844771:dw|
jimthompson5910 (jim_thompson5910):
what I'm talking about is this segment (in black)
|dw:1358891880746:dw|
OpenStudy (anonymous):
ohhh C and D sorry lol
jimthompson5910 (jim_thompson5910):
you mean segment CD right?
OpenStudy (anonymous):
yes hhaha lol
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
that's the shared side between the two triangles that overlap
jimthompson5910 (jim_thompson5910):
CD = CD by the reflexive property
jimthompson5910 (jim_thompson5910):
then you can say those two overlapping triangles are congruent by the ASA property
OpenStudy (anonymous):
okay, so what would our whole overall problem look like? ill do it, and you see if it looks correct
jimthompson5910 (jim_thompson5910):
alright
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
BCD=EDC|GIVEN
BCD=ECD|GIVEN
so CD=CD by the reflexive property
the two overlapping triangles are congruent by the ASA property
would this be what it look like?
jimthompson5910 (jim_thompson5910):
you'll have to be specific by actually naming the triangles
OpenStudy (anonymous):
BCD=EDC|GIVEN
BCD=ECD|GIVEN
so CD=CD by the reflexive property
BCD and EDC are congruent by the ASA property
how about this?^^
jimthompson5910 (jim_thompson5910):
you nailed it
OpenStudy (anonymous):
awesome! okay how about the next one now:)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
oh you might want to say triangles BCD and EDC are congruent by the ASA property
so you don't confuse them with angles
OpenStudy (anonymous):
okay!
jimthompson5910 (jim_thompson5910):
ok how do we get started on the next one
OpenStudy (anonymous):
we have to start with what we are given.
jimthompson5910 (jim_thompson5910):
exactly, so go ahead and state that
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
im not sure how that to start this one because Ive never done one with a midpoint in it, but ill try real quik
jimthompson5910 (jim_thompson5910):
well you start off by stating that D is the midpoint of AC (given)
then you use the definition of midpoint to say that AD = CD
OpenStudy (anonymous):
BDC=BDA|GIVEN
BCD=BAD|GIVEN
RIGHT?
jimthompson5910 (jim_thompson5910):
where does it say that BCD=BAD is given?
OpenStudy (anonymous):
actually no lol
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
but the first one is given
jimthompson5910 (jim_thompson5910):
so add that on
OpenStudy (anonymous):
AD=CD|GIVEN
right?
jimthompson5910 (jim_thompson5910):
AD = CD not because it's given, but by the definition of midpoint
jimthompson5910 (jim_thompson5910):
A midpoint cuts a line segment into two equal halves
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so then how do i find my other given?
jimthompson5910 (jim_thompson5910):
You're done with you're givens
OpenStudy (anonymous):
oh so theirs only one given then
jimthompson5910 (jim_thompson5910):
Now you need one more side or one more angle, here is a visual hint:
|dw:1358892974213:dw|