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OpenStudy (anonymous):

can someone help me with these 3 proofs, I have attached the file.. it has to get done by today! and i really appreciate it:) medals rewarded!

OpenStudy (anonymous):

OpenStudy (anonymous):

@roberman228

OpenStudy (anonymous):

okay:)

OpenStudy (anonymous):

yea, ive tried google

OpenStudy (anonymous):

@whpalmer4 can you help?

OpenStudy (anonymous):

@jim_thompson5910 can you help me with these couple of questions about geometry proofs?

jimthompson5910 (jim_thompson5910):

how far did you get on #2

OpenStudy (anonymous):

um i think i finished that one, not sure let me check

jimthompson5910 (jim_thompson5910):

ok post what you got

OpenStudy (anonymous):

im not so sure how to do it?

jimthompson5910 (jim_thompson5910):

or just write it out here

OpenStudy (anonymous):

like what do you mean?

OpenStudy (anonymous):

# 2 im not sure what to do

OpenStudy (anonymous):

what is the first step i need to do @jim_thompson5910 ?

jimthompson5910 (jim_thompson5910):

well start with what you are given

OpenStudy (anonymous):

so would it be BCD=EDC BCD=ECD

OpenStudy (anonymous):

both are given?

jimthompson5910 (jim_thompson5910):

good, start off saying those two sets of angles are congruent because that's given

OpenStudy (anonymous):

so then it would look like this? BCD=EDC|GIVEN BCD=ECD|GIVEN and then now what?

jimthompson5910 (jim_thompson5910):

what segments can you say for sure are congruent

OpenStudy (anonymous):

uuhmm not so sure.

OpenStudy (anonymous):

i would have to say that BCD and BED are congruent right?

jimthompson5910 (jim_thompson5910):

what segment is between angles BCD and EDC

OpenStudy (anonymous):

is it just one segment?

jimthompson5910 (jim_thompson5910):

yes do you see it?

OpenStudy (anonymous):

CDE?

jimthompson5910 (jim_thompson5910):

segment, not angle

OpenStudy (anonymous):

F?

jimthompson5910 (jim_thompson5910):

that's a point, not a segment

OpenStudy (anonymous):

whats a segment?

jimthompson5910 (jim_thompson5910):

there's the figure |dw:1358891844771:dw|

jimthompson5910 (jim_thompson5910):

what I'm talking about is this segment (in black) |dw:1358891880746:dw|

OpenStudy (anonymous):

ohhh C and D sorry lol

jimthompson5910 (jim_thompson5910):

you mean segment CD right?

OpenStudy (anonymous):

yes hhaha lol

jimthompson5910 (jim_thompson5910):

that's the shared side between the two triangles that overlap

jimthompson5910 (jim_thompson5910):

CD = CD by the reflexive property

jimthompson5910 (jim_thompson5910):

then you can say those two overlapping triangles are congruent by the ASA property

OpenStudy (anonymous):

okay, so what would our whole overall problem look like? ill do it, and you see if it looks correct

jimthompson5910 (jim_thompson5910):

alright

OpenStudy (anonymous):

BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property the two overlapping triangles are congruent by the ASA property would this be what it look like?

jimthompson5910 (jim_thompson5910):

you'll have to be specific by actually naming the triangles

OpenStudy (anonymous):

BCD=EDC|GIVEN BCD=ECD|GIVEN so CD=CD by the reflexive property BCD and EDC are congruent by the ASA property how about this?^^

jimthompson5910 (jim_thompson5910):

you nailed it

OpenStudy (anonymous):

awesome! okay how about the next one now:)

jimthompson5910 (jim_thompson5910):

oh you might want to say triangles BCD and EDC are congruent by the ASA property so you don't confuse them with angles

OpenStudy (anonymous):

okay!

jimthompson5910 (jim_thompson5910):

ok how do we get started on the next one

OpenStudy (anonymous):

we have to start with what we are given.

jimthompson5910 (jim_thompson5910):

exactly, so go ahead and state that

OpenStudy (anonymous):

im not sure how that to start this one because Ive never done one with a midpoint in it, but ill try real quik

jimthompson5910 (jim_thompson5910):

well you start off by stating that D is the midpoint of AC (given) then you use the definition of midpoint to say that AD = CD

OpenStudy (anonymous):

BDC=BDA|GIVEN BCD=BAD|GIVEN RIGHT?

jimthompson5910 (jim_thompson5910):

where does it say that BCD=BAD is given?

OpenStudy (anonymous):

actually no lol

jimthompson5910 (jim_thompson5910):

but the first one is given

jimthompson5910 (jim_thompson5910):

so add that on

OpenStudy (anonymous):

AD=CD|GIVEN right?

jimthompson5910 (jim_thompson5910):

AD = CD not because it's given, but by the definition of midpoint

jimthompson5910 (jim_thompson5910):

A midpoint cuts a line segment into two equal halves

OpenStudy (anonymous):

so then how do i find my other given?

jimthompson5910 (jim_thompson5910):

You're done with you're givens

OpenStudy (anonymous):

oh so theirs only one given then

jimthompson5910 (jim_thompson5910):

Now you need one more side or one more angle, here is a visual hint: |dw:1358892974213:dw|

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