Question

Please Help ASAP!?
What is the solution of the equation?
3^5√(x+2)^3+3=27

Answer 1

subtract 3, divide by 3^5, raise both sides to the 1/3 power, raise both sides to the 2 power, subtract 2.

Answer 2

This is assuming that your sqrt looks like this (sqrt(x+2))^3

Answer 3

\[3^5\sqrt{(x+2)^{3}}+3=27\]
Divide by 3 to both sides.
\[3^4\sqrt{(x+2)^{3}}+1=9\]
\[3^4\sqrt{(x+2)^{3}}=9-1\]
\[\sqrt{(x+2)^{3}}=\frac{ 8 }{ 3^{4} }\]
\[\sqrt{(x+2)^{3}}=\frac{ 8 }{ 81 }\]
\[(x+2)^{3}=\frac{ 64 }{ 6561 }\]
\[x+2=\frac{ 4 }{ \sqrt[3]{6561} }\]
\[x=\frac{ 4 }{ \sqrt[3]{6561} }-2\]
\[x=\frac{ 4-2\sqrt[3]{6561} }{ \sqrt[3]{6561} }\]

Answer 4

so x=4-2^3√6561/^3√6561 is my answer?

Answer 5

@sophiasmommy94 was that the right answer?

Answer 6

I hope so