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OpenStudy (anonymous):
Find the molarity of a solution made from 734 g of Li2SO4 and 2.5 L of water
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OpenStudy (anonymous):
Molarity= Moles/Liter 1mole Li2So4= 109.94g so 734g (given)/ 109.94g(1mole )= 6.68 moles 6.68moles/2.5L = 2.67M
OpenStudy (anonymous):
thanks
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