What is the length of the hypotenuse? (Picture below.)
Use what i just taught you to find the opposite side length. Then use the Pythagorean theorem.
\[\cos \theta=\frac{\text{adjacent side}}{\text{hypotenuse}}\]
Tan = 45?
Ohh
we have an angle, an an adjacent side length, we are solving for the hypotenuse
Or you can do it Unkles way but i pref this way ^^
The one you showed me?
Tan(45)=x/3 right?
Correct. the tan of 45 is 1 btw so its 1 = x/3
x=3
Or in other words 1*3.. So now that you got the length of 2 sides you can use Pythagorean theorem. To solve for the hypotenuse. (a^2 + b^2 = c^2)
Where do I plug them in?
Notice that this is a 45-45-90 triangle. You can use the Pythagoras theorem, with both legs = 3, and solve for the hypotenuse. Also, the ratio of the lengths of the sides of a 45-45-90 triangle is 1 : 1 : sqrt(2)
Let c be the Hypotenuse. So it would be (3^2 + 3^2 = c^2) 9+9=18 \[\sqrt{18}\] = 4.24 Or if you wanted to be more precise you could do simplify it to \[3\sqrt{2}\]
a^2+b^2=c^2 3^2+3^2=c^2
Thanks!
Correct. 9 + 9 = c^2 etc.
I think in your case tho 4.24 is plenty precise enough.
This is a trig problem
Why trig? Just good old Pythagoras is enough.
Yes it is, & @TwitchyJoe I do the same with this one right?
Both legs are "a" a^2 + a^2 = 10^2
Yes only this time you use Sin.
So Sin(45) = x/10
\[-5\sqrt{2}\]
You are doing your math slightly wrong.. Its just Sin45 which is 0.7* 10
Opps i wrote 0.7, it should be 0.71*10
So your answer would be 7.1
Thank you again for explaining and being patient.
The answer would then be 71 right?
7.1 Yes. Also close the question after you are done.
Dont forget the ---> .
Trying to point to the dot lol
LOL okaaay, the length of the opposite side of 45 is 7.1.
Join our real-time social learning platform and learn together with your friends!