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Mathematics 11 Online
OpenStudy (anonymous):

triangle ABC is equalateral. Find the height of side BD

OpenStudy (anonymous):

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OpenStudy (anonymous):

you need to use trig. ratios. All of the angles in the equilateral triangle are 45 degrees.

OpenStudy (anonymous):

ex. sin(A) = (BD)/(BA) where BD is the length of BD and BA is the length of BA

OpenStudy (anonymous):

A = 45 degrees, so sin(45) = sqrt(2)/2

OpenStudy (anonymous):

so what would our answer be?

OpenStudy (anonymous):

it would depend on the length of the sides

OpenStudy (anonymous):

4 sqrt (2)

OpenStudy (anonymous):

This problem does not require trig ratios. DC is 4 BD^2 + 4^2 = 8^2 BD = 4 times sqrt(3)

OpenStudy (anonymous):

Also, the 3 angles of an equilateral triangle are 60 degrees. When working with the triangle BDC, and IF you had a trig problem (you don't need trig here), you would use 30-60-90 trig ratios. But again, BD is gotten from the Pythagorean Theorem and is the answer from my first post.

OpenStudy (anonymous):

so whats our answer

OpenStudy (anonymous):

BD = 4 times sqrt(3)

OpenStudy (anonymous):

And the reason that that is the answer: [(4) times sqrt(3)]^2 + 4^2 = 8^2 (16)(3) + 16 = 64

OpenStudy (anonymous):

You might like the way this looks a little better:\[4 \times \sqrt{3}\]and that is approximately: 6.928

OpenStudy (anonymous):

Hope this is going good for you. Nice working with you again @katlin95

OpenStudy (anonymous):

thanks!:)

OpenStudy (anonymous):

You're very welcome!

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