triangle ABC is equalateral. Find the height of side BD
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you need to use trig. ratios. All of the angles in the equilateral triangle are 45 degrees.
ex. sin(A) = (BD)/(BA) where BD is the length of BD and BA is the length of BA
A = 45 degrees, so sin(45) = sqrt(2)/2
so what would our answer be?
it would depend on the length of the sides
4 sqrt (2)
This problem does not require trig ratios. DC is 4 BD^2 + 4^2 = 8^2 BD = 4 times sqrt(3)
Also, the 3 angles of an equilateral triangle are 60 degrees. When working with the triangle BDC, and IF you had a trig problem (you don't need trig here), you would use 30-60-90 trig ratios. But again, BD is gotten from the Pythagorean Theorem and is the answer from my first post.
so whats our answer
BD = 4 times sqrt(3)
And the reason that that is the answer: [(4) times sqrt(3)]^2 + 4^2 = 8^2 (16)(3) + 16 = 64
You might like the way this looks a little better:\[4 \times \sqrt{3}\]and that is approximately: 6.928
Hope this is going good for you. Nice working with you again @katlin95
thanks!:)
You're very welcome!
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