Rewrite with only sin x and cos x. sin 2x - cos x Options are: 2 sin x cos^2x sin x cos x (2 sin x - 1) 2 sin x
Tell me what you get when you expand \[\sin(2x)\] Use your double angle results. \[\sin(2x)=\sin(x+x)\] \[\sin(x+x)=?\]
Doesn't sin 2x = 2 sin x cos x?
Does that have anything to do with this problem?
Yes.
That's exactly right.
You substitute 2sinxcosx with sin(2x).
so factorise 2sinxcosx-cosx for me please.
Well since there is cos x on both side of the equation would you cancel them and then you are left with just 2 sin x?
Do you know what factorising is?
For example, can you factorise: \[x^2+x\]?
would it be x(x+1)
Correct! That's how you would go about factorising this: 2sinxcosx-cosx
Take the common factor in both terms and then you can factorise it.
Would the common factor would be cos x?
Yes!
So the answer would be cos x(2 sin x-1)?
Correct. Well Done.
Thank you for your help! :)
No worries.
useful to know sin or cos shifted a certain amount will equal cos or sin. so in other words an example sin(x+a)=cos (x)
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