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Mathematics 19 Online
OpenStudy (anonymous):

Im so freaking confused and stupid help me

OpenStudy (anonymous):

All of the questions are based off of this word problem: efren leaves home at 9am and walks 4 mph. his bro greg leaves 1/2 hr later and runs 8.5 mph in the same direction as efren. predict the time at which gred will catch up to efren

OpenStudy (anonymous):

write an expression for the distance of greg's travels per hour let h stand for time in hours!

OpenStudy (anonymous):

write an expression for the distance efren travels per hour plus the distance he will have traveled when greg leaves the house

jimthompson5910 (jim_thompson5910):

if greg runs at a speed of 8.5 mph and he runs for h hours, how far will he run?

OpenStudy (anonymous):

i dont know

OpenStudy (anonymous):

im really stupid no joke when it comes to math

jimthompson5910 (jim_thompson5910):

you're not stupid, you just need more practice

jimthompson5910 (jim_thompson5910):

say he ran for 1 hour how far would he get?

OpenStudy (anonymous):

8.5 miles?

jimthompson5910 (jim_thompson5910):

good, in 2 hours he will go ____ miles

OpenStudy (anonymous):

17

jimthompson5910 (jim_thompson5910):

how did you get that

OpenStudy (anonymous):

8.5 x 2

jimthompson5910 (jim_thompson5910):

so in 3 hours, he will run 8.5 x 3 = 25.5 miles so in 4 hours, he will run 8.5 x 4 = 34 miles .... in general... if he runs h hours (some unknown amount of hours), then he will run 8.5 x h or just 8.5h miles

jimthompson5910 (jim_thompson5910):

so if d = distance traveled, then d = 8.5h

OpenStudy (anonymous):

oh okay so it says write an expression but im confused on how to write one

jimthompson5910 (jim_thompson5910):

ok so you'll just write 8.5h

jimthompson5910 (jim_thompson5910):

8.5h is the expression d = 8.5h is the equation

OpenStudy (anonymous):

what about the other expression i have to write for efren

jimthompson5910 (jim_thompson5910):

keep in mind that greg started 1/2 hour later than efren

jimthompson5910 (jim_thompson5910):

so you have to account for that

OpenStudy (anonymous):

oh & it says plus the distance he wil he will have traveled when greg leaves

jimthompson5910 (jim_thompson5910):

let's assume they both start at the same time (9:30 am) if efren walks at 4 mph and he does this for h hours, then he will walk a total of 4h miles

OpenStudy (anonymous):

so would it be greg leaving at 9:30??

jimthompson5910 (jim_thompson5910):

but this isn't the whole story because efren leaves at 9:00 am instead of 9:30 am so he's got a 1/2 hr head start

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

but i dont know what the distance formula is either thats one of the questions

jimthompson5910 (jim_thompson5910):

so you have to add in the fact that he walked some additional distance in that half hour where he got the head start if he walked 0.5 hours (1/2 hr) at a speed of 4 mph, then he would have walked 4*0.5 = 2 miles

jimthompson5910 (jim_thompson5910):

distance formula: distance = rate x time d = r x t d = rt

jimthompson5910 (jim_thompson5910):

rate is known as speed

OpenStudy (anonymous):

oh yeah i remember that lol

OpenStudy (anonymous):

so he walked 2 miles??

jimthompson5910 (jim_thompson5910):

yes in that half hour where he got the head start

jimthompson5910 (jim_thompson5910):

so he walked 2 miles in the first half hour then he walked an additional 4h miles after 9:30 am

jimthompson5910 (jim_thompson5910):

in total, efren walked 2+4h or 4h + 2 miles

OpenStudy (anonymous):

so what expression would be for efren plus the distance he would of traveled when greg left

jimthompson5910 (jim_thompson5910):

4h + 2

jimthompson5910 (jim_thompson5910):

4h is the amount he traveled when greg left 2 is the amount he traveled when greg was still at home

OpenStudy (anonymous):

oh i see, sorry ive been up all night doing this and im annoyed and fed up :(

jimthompson5910 (jim_thompson5910):

thats ok

jimthompson5910 (jim_thompson5910):

to find out when the two will meet, you just set the two expressions equal to one another

jimthompson5910 (jim_thompson5910):

8.5h = 4h + 2 and solve for h

OpenStudy (anonymous):

so the next question is weird it says write an equation setting the distance expressions in steps 3 and 4 equal

jimthompson5910 (jim_thompson5910):

yep you want to find out when the two will walk the same distance (ie find out when/where the two will meet)

OpenStudy (anonymous):

could you help me figure that out ill try to do most my self

jimthompson5910 (jim_thompson5910):

well you see how i got 8.5h = 4h + 2 right?

OpenStudy (anonymous):

yup!

OpenStudy (anonymous):

you added the time he waited to the expression

jimthompson5910 (jim_thompson5910):

ok great, subtract 4h from both sides 8.5h = 4h + 2 8.5h - 4h = 2 4.5h = 2 what's next?

OpenStudy (anonymous):

4.5 = 2 - 2 ?

jimthompson5910 (jim_thompson5910):

4.5h is the same as 4.5 x h

jimthompson5910 (jim_thompson5910):

how do you undo multiplication

OpenStudy (anonymous):

OH! :) I know!! 4.5h/4.5 2/4.5

OpenStudy (anonymous):

you divide 2 by 4.5

OpenStudy (anonymous):

am i right?

jimthompson5910 (jim_thompson5910):

you are correct

jimthompson5910 (jim_thompson5910):

so h = ??

jimthompson5910 (jim_thompson5910):

2/4.5 = ?

OpenStudy (anonymous):

h = 0.4 repeating (so line over the 4)

jimthompson5910 (jim_thompson5910):

so that's the rough approximation of how many hours it will take (after 9:30) for the two to meet

jimthompson5910 (jim_thompson5910):

and for the two to travel the same distance

jimthompson5910 (jim_thompson5910):

convert to minutes to get: 0.444*60 = 26.64 so it will take about 26.64 minutes

OpenStudy (anonymous):

thank you very much for helping me i wish i was as smart as you i struggle just to keep my B- average

jimthompson5910 (jim_thompson5910):

I'm sure you'll do fine, just keep your head up and keep practicing

OpenStudy (anonymous):

thank you jim have a nice day!

jimthompson5910 (jim_thompson5910):

you're welcome

jimthompson5910 (jim_thompson5910):

you too

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