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Mathematics 22 Online
OpenStudy (anonymous):

Simplifying this question.

OpenStudy (anonymous):

\[\sqrt{4x + 9} = \sqrt{4x} +\sqrt{9}\] Is this right? If so... Why can I solve it that way?

OpenStudy (anonymous):

the whole problem \[\sqrt{4x + 9} = x + 3\]

OpenStudy (anonymous):

\[(\sqrt{4x + 9})^{2} = ( x + 3) ^{2}\]

OpenStudy (anonymous):

And simplify from there... But the first post I'm not sure about it! Can someone tell me why?

OpenStudy (anonymous):

The first post of yours is NOT correct because, consider this example, \[\sqrt{4+9} = \sqrt{13}\] which, if I follow your first post will become, \[\sqrt{4+9} = \sqrt{4} + \sqrt{9} = 2 + 3 = 5\] or if I do it like this, \[\sqrt{4+9} = \sqrt{4+4+4+1} = \sqrt{4}+\sqrt{4}+\sqrt{4} +\sqrt{1} = 7\] From this, since you can break the additions in and way, you would be having many impossible answers, SO ONLY FIRST OF THE WAYS , THAT IS , \[\sqrt{13}\] IS THE CORRECT ONE...

OpenStudy (anonymous):

*ANY* IN PLACE OF *AND*

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

My pleasure :-)

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