Question

Write the complex number in the form a + bi sqrt6(cos 315° + i sin 315°)
PLEASE HELP

Answer 1

options are:

Answer 2

@jim_thompson5910 could you help with this last one :/ ? Im so sorry

Answer 3

what is the cosine of 315 degrees

Answer 4

sqrt2/2

Answer 5

@jim_thompson5910

Answer 6

what about the sine of 315 degrees

Answer 7

-1/sqrt2 @jim_thompson5910

Answer 8

or -sqrt(2)/2

Answer 9

sorry about that youre right ./.... typo @jim_thompson5910

Answer 10

so this means that we have this so far


\[\Large \sqrt{6}\left(\cos(315) + i\sin(315)\right)\]


\[\Large \sqrt{6}\left(\frac{\sqrt{2}}{2} - i*\frac{\sqrt{2}}{2}\right)\]

Answer 11

so like (2-2i) sqrt3 @jim_thompson5910

Answer 12

how did you get that

Answer 13

I have no clue ... I messed up on the way Im thinking it was either A or C but Im leaning towards A

Answer 14

@jim_thompson5910

Answer 15

one sec

Answer 16

okay

Answer 17

\[\Large \sqrt{6}\left(\cos(315) + i\sin(315)\right)\]


\[\Large \sqrt{6}\left(\frac{\sqrt{2}}{2} - i*\frac{\sqrt{2}}{2}\right)\]


\[\Large \sqrt{6}*\left(\frac{\sqrt{2}}{2}\right) - i*\sqrt{6}*\left(\frac{\sqrt{2}}{2}\right)\]


\[\Large \frac{\sqrt{6}*\sqrt{2}}{2} - i*\frac{\sqrt{6}*\sqrt{2}}{2}\]


\[\Large \frac{\sqrt{6*2}}{2} - i*\frac{\sqrt{6*2}}{2}\]


\[\Large \frac{\sqrt{12}}{2} - i*\frac{\sqrt{12}}{2}\]


\[\Large \frac{\sqrt{4*3}}{2} - i*\frac{\sqrt{4*3}}{2}\]


\[\Large \frac{\sqrt{4}*\sqrt{3}}{2} - i*\frac{\sqrt{4}*\sqrt{3}}{2}\]


\[\Large \frac{2*\sqrt{3}}{2} - i*\frac{2*\sqrt{3}}{2}\]


\[\Large \sqrt{3} - i*\sqrt{3}\]


\[\Large \sqrt{3} - \sqrt{3}*i\]

Answer 18

Thank you !!!

Answer 19

np