Question

x^2+1/x-3 +x-5/x+3

Answer 1

\[\frac{ x^2+1 }{ x-3? }+\frac{ x-5 }{ x+3? }\]

Answer 2

you need common denominator ... to do that, multiply separate denominators together
to keep equality, you must then also multiply same thing on numerator as well

\[\frac{(x^{2} +1)}{(x-3)}*\frac{(x+3)}{(x+3)} + \frac{(x -5)}{(x+3)}*\frac{(x-3)}{(x-3)} \]

Answer 3

ok so would i cx the like terms meani............

Answer 4

??
yes you will multiply out the numerator and then add like terms

Answer 5

\[\frac{x^2+1 ? }{x-3 ? }\]

Answer 6

x(x+1) all over x-3

Answer 7

x(x+1) = x^2 +x which is not the same

Answer 8

(x+1)(x-1)

Answer 9

are you trying to factor "x^2 +1" ??

(x+1)(x-1) = x^2 -1 ..... not the same

Answer 10

yes i am is that not what im supposed to do

Answer 11

well its not necessary because to combine the fractions you need to multiply it out then add like terms

but in general, factoring whenever possible is always good :)
however "x^2 +1" does not factor

Answer 12

so its in its simplest form?? so do i multiply.....im so confused

Answer 13

you may want to review factoring concepts

yes once you've changed denominator to common denominator....expand each numerator and combine like terms .... then you have a single fraction

Answer 14

the denomminator is (x-3) (x+3) is it not??

Answer 15

correct

Answer 16

\[\frac{ x^2+1 }{ ? x-3}\frac{}{ ?x+3 }\]

Answer 17

or do i need to multiply by x+3 1st

Answer 18

yes multiply by (x+3)/(x+3)

Answer 19

X^2+1/x-3 + x-5/x+3
the LCD is (x-3)(x+3)
(x-3)(x+3)[x^2+1/x-3] + (x-3)(x+3)[x-5/x+3]
cross out like thearms
(x-3)(x^2+1) + (x-3)(x-5)
X^3+x+3x^2+3+x^2-5x-3x+15
X^3+3x^2+X+3+x^2-8x+15
X^3+4x^2-7x+15

Answer 20

\[x \neq (-1,-2,-3)\]