Question

Can someone help : x^2 +y^2 + 6x -6y -46=0 graph the circle
I am getting messed up when I have to complete the square and put in standard form. Thanks!

Answer 1

complete the square twice. Once with x and once with y.

Answer 2

When completing the square for x, ignore all the terms with y in it.

Answer 3

\[x^2+6x-46=0\]
Complete the square for this.

Answer 4

(x^2 +6x) (6y +y^2)=46

Answer 5

x(x +6)^2 = 46

Answer 6

That's not how you complete the square.

Answer 7

\[x^2+bx+c=0\]
\[(x+\frac{b}{2})^{2}=-c+(\frac{b}{2})^2\]

Answer 8

\[x^2 +y^2 + 6x -6y -46=0\]
\[x^2+6x+y^2-6y=46\]
\[(x+3)^2+y^2-6y=46+9\]
\[(x+3)^2+(y-3)^2=46+9+9\]
\[(x+3)^2+(y-3)^2=64\]

Answer 9

the equation is,
x^2+y^2+6x-6y-46=0
=> x^2+6x+9+y^2-6x+9-18-46=0
=>(x+3)^2+(y-3)^2=18+46=64=8^2
which is of the form (x-a)^2+(y-b)^2=r^2
so center of the circle is (a,b) with radius r.
here center is (-3,3) and radius is 8 unit