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OpenStudy (aravindg):
solve for r2?
OpenStudy (anonymous):
solve for r
OpenStudy (aravindg):
is it \[\large r^2?\]
OpenStudy (aravindg):
did you mean
\[x=r^2-y^2\]
OpenStudy (anonymous):
I'm sorry. Yes, x=sqrt of r squared minus sqrt of y squared, solve for r
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OpenStudy (aravindg):
ok then add \(y^2\) on both sides what do you get ?
OpenStudy (anonymous):
first, how do you get the square beside the variable
OpenStudy (aravindg):
use equation button below
OpenStudy (anonymous):
uhhh nope...where
OpenStudy (anonymous):
ohhh, i see it now
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OpenStudy (aravindg):
:)
OpenStudy (anonymous):
x\[x ^{2}+y ^{2}=r ^{2}\]
OpenStudy (aravindg):
is it \[x^2?\]
OpenStudy (anonymous):
yes
OpenStudy (aravindg):
ok now you got equation for \(r^2\) .Now take square root on both sides to get r
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OpenStudy (aravindg):
what will that be?
OpenStudy (anonymous):
Okay...I'm new to this site and I'm having a hard time with the "equation" button. I know the answer will be r = sqrt of x sqrd + y sqrd. My question...why does the square remove from the r and not the x and y?
OpenStudy (aravindg):
simply because square root does not distribute to each term
OpenStudy (aravindg):
\[\large \sqrt{a+b} \neq \sqrt{a} +\sqrt{b}\]
OpenStudy (aravindg):
i think that clears ur doubt
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OpenStudy (anonymous):
Yes, it does. Thank you for ur patience. I'm going to play around with the equation buton. :-)
OpenStudy (aravindg):
lols all the best !! if you hav any problem about using the site ,fell free to ask me :)
OpenStudy (aravindg):
and @ericalashawn
\[\huge \color{green}{\text{WELCOME TO OPENSTUDY!}}\]