Question

Given: D is the midpoint of AC, ∠BDA≅∠BDC. Prove ΔABD ≅ΔCBD

Answer 1

You know those are the same triangles as the given one but just in a different order? And midpoint is the same thing as a bisector.

Answer 2

ADC = AD + DC
ABC = ABD + CBD
Finally Midpoint of AC is D
Therefore within the compound of the triangle ΔABC is the reflective/mirror image from point BD(except angles, i.e ΔABD is mirroring ΔCBD)
Since the above, so ΔABD ≅ΔCBD

Answer 3

@umm... any doubts?

Answer 4

well im having trouble understanding this and im new to this openstudy so i don't know how to use this
lol so yeah

Answer 5

@AravindG