Given: D is the midpoint of AC, ∠BDA≅∠BDC. Prove ΔABD ≅ΔCBD

Question

anonymous · Answer

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anonymous · Answer

You know those are the same triangles as the given one but just in a different order? And midpoint is the same thing as a bisector.

anonymous · Answer

ADC = AD + DC
ABC = ABD + CBD
Finally Midpoint of AC is D
Therefore within the compound of the triangle ΔABC is the reflective/mirror image from point BD(except angles, i.e ΔABD  is mirroring ΔCBD)
Since the above, so ΔABD ≅ΔCBD

aravindg · Answer

@umm...  any doubts?

anonymous · Answer

well im having trouble understanding this and im new to this openstudy so i don't know how to use this 
lol so yeah

anonymous · Answer

@AravindG