Question

Find the solution to the equation 64^(4 – x) = 4^(2x)?

Answer 1

Notice:\[64 ^{4 - x} = (4^3)^{4 - x}\]

Answer 2

Oh, 4^3 is equal to 64.

So would I make it: \[64^{4-x}=64^{4-x}\]

Answer 3

:\ So look in your text book yet?

Answer 4

Sadly I don't have a textbook, I do online school. I've been trying to reach my teacher all morning but she hasn't responded :/

Answer 5

I do online school to I know how it feels when a teacher doesn't reach you back =-=

Answer 6

do what @ParthKohli said
rewrite \(64\) as \(4^3\)
this means \(64^{4-x}=4^{3(4-x)}=4^{12-3x}\)

Answer 7

then you know \(12-3x=2x\) so you can solve for \(x\)

Answer 8

do what satellite73 tells you to do
if you can create the same bases
then you can set the exponents equal to each other and solve for x

Answer 9

Thank you everyone for the help, I understand the problem now.

Answer 10

yw