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Mathematics 14 Online
OpenStudy (anonymous):

PLSPLSPLSPLS HELP. In the diagram below, is an altitude of ABD. What is the length of ? If necessary, round your answer to two decimal places. (Picture below.)

OpenStudy (anonymous):

OpenStudy (zehanz):

First try to prove triangle ACB and ABD are similar. Similar triangles have proportional sides (meaning sides in the big triangle are a constant factor times the sides in the small one). Further hint: you may need the Pythagorean Theorem as well...

OpenStudy (anonymous):

a^2+b^2=c^2. Where do I input 16 and 30?

OpenStudy (anonymous):

16 = a, 30 = c?

OpenStudy (zehanz):

a and b are the rectagular sides, c is the hypothenuse

OpenStudy (anonymous):

16^2+b^2=30^2 B= 25.38?

OpenStudy (zehanz):

No, a and b are the rectangular sides. In triangle ACB these are 16 and 30, so c²=16²+30²=256+900=1156, so c=34.

OpenStudy (zehanz):

So AB=34.

OpenStudy (anonymous):

Now what do I do to find CD?

OpenStudy (anonymous):

@ZeHanz

OpenStudy (zehanz):

ACB and ABD are similar, because they both have a right angle, and they have angle A in common. Similar triangles have proportional sides, which means:\[\frac{ AC }{ AB }=\frac{ AB }{ AD }\] (read as: one side in first triangle : same side in other one= same number. Because in the above equation, you know 3 out of four lengths, you can calculate the fourth (AD). Once AD is known, you get CD = AD-16.

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