Integrate: cot^2(x+pi/4) (See inside)
\[\int\limits \cot^{2}(x+\frac{\pi}{4})\] I know that the answer is eventually something close to\[-\csc(x+\frac{\pi}{4})\]
But the answer key gives \[-\csc(x+\frac{\pi}{4})-x \] So what part of the chain rule am I forgetting?
\[\large \color{salmon}{\cot^2x+1=\csc^2x} \qquad \rightarrow \qquad \color{salmon}{\cot^2x=\csc^2x-1}\]Using this pink identity gives us,\[\large \int\limits \cot^2(x+\frac{\pi}{4})dx \qquad \rightarrow \qquad \int\limits \csc^2(x+\frac{\pi}{4})-1\quad dx\]
This shouldn't be too difficult to integrate. I know cotangents and cosecants don't come up as often as the others but this is still a good one to remember :)
\[\large \int\limits \sec^2x dx = \tan x, \qquad \qquad \int\limits \csc^2x dx=-\cot x\]
Thanks. Didn't realize it was an identity.
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