Question

Help , Calculus!

Answer 1

The average (mean) of \[\sqrt{x}\] over the interval \[0 \le x \le 2\] is..?

Answer 2

The answer is given again . it is \[\frac{ 2 }{ 3 }\sqrt{2}\]

Answer 3

\[\huge f_{ave}=\frac{1}{b-a}\int\limits_a^b f(x) dx\]

Answer 4

\[\huge f_{ave}=\frac{1}{2-0}\int\limits_0^2 x^{1/2}dx\]

Answer 5

This one seems pretty easy :D
I think you can do it.

Answer 6

hm.. i'll try :)

Answer 7

i got... \[\frac{ 2^{\frac{ 3 }{ 2 }} }{ 3 }\] ... :(

Answer 8

Yes good :)

Answer 9

Make sure you can convert things from rational expressions to roots+powers, otherwise you'll have a tough time identifying when you have the correct answer.

Answer 10

ahh that's why i kept on thinking that i did it wrong! haha