Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

If mR = 28°, find mO. The figure is not drawn to scale. 152° 28° 62° 56°

OpenStudy (anonymous):

OpenStudy (unklerhaukus):

|dw:1358997326075:dw|

OpenStudy (anonymous):

what do i do?

OpenStudy (unklerhaukus):

hmm im not sure at the moment

jimthompson5910 (jim_thompson5910):

Hint: Use the inscribed angle theorem

jimthompson5910 (jim_thompson5910):

|dw:1358997867970:dw|

jimthompson5910 (jim_thompson5910):

That's a pic of a central angle

jimthompson5910 (jim_thompson5910):

here is an inscribed angle (that subtends, or cuts, the same arc) |dw:1358997916101:dw|

jimthompson5910 (jim_thompson5910):

all inscribed angles that cut the same arc as the central angle will be half as large as the central angle, so if we label the angles the following |dw:1358997960316:dw| then y = (1/2)x or x = 2y according to the inscribed angle theorem

OpenStudy (anonymous):

I'm still confused :(

jimthompson5910 (jim_thompson5910):

say we know that the central angle is 90 degrees, this would make the inscribed angle to be (1/2)*90 = 45 degrees |dw:1358998093946:dw|

OpenStudy (anonymous):

so "O" in my pic is the inscribed angle?

jimthompson5910 (jim_thompson5910):

no, O is the center of the circle

OpenStudy (unklerhaukus):

mO

jimthompson5910 (jim_thompson5910):

angle NOQ is the central angle angle NRQ is the inscribed angle

jimthompson5910 (jim_thompson5910):

angle O is the central angle

jimthompson5910 (jim_thompson5910):

because it's in the center of the circle

jimthompson5910 (jim_thompson5910):

inscribed angle = (1/2)*[ central angle ]

jimthompson5910 (jim_thompson5910):

what is the inscribed angle

jimthompson5910 (jim_thompson5910):

what is the measure of NRQ

OpenStudy (anonymous):

at the risk of sounding stupid i am not sure at this point

jimthompson5910 (jim_thompson5910):

angle R = angle NRQ

OpenStudy (anonymous):

so 28

jimthompson5910 (jim_thompson5910):

inscribed angle = (1/2)*[ central angle ] 28 = (1/2)*[ central angle ] find the "central angle"

OpenStudy (anonymous):

56

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

Thank you !sorry it took so long...

jimthompson5910 (jim_thompson5910):

|dw:1358999385009:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!