If mR = 28°, find mO. The figure is not drawn to scale.
152°
28°
62°
56°
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OpenStudy (anonymous):
OpenStudy (unklerhaukus):
|dw:1358997326075:dw|
OpenStudy (anonymous):
what do i do?
OpenStudy (unklerhaukus):
hmm im not sure at the moment
jimthompson5910 (jim_thompson5910):
Hint:
Use the inscribed angle theorem
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jimthompson5910 (jim_thompson5910):
|dw:1358997867970:dw|
jimthompson5910 (jim_thompson5910):
That's a pic of a central angle
jimthompson5910 (jim_thompson5910):
here is an inscribed angle (that subtends, or cuts, the same arc)
|dw:1358997916101:dw|
jimthompson5910 (jim_thompson5910):
all inscribed angles that cut the same arc as the central angle will be half as large as the central angle, so if we label the angles the following
|dw:1358997960316:dw|
then y = (1/2)x or x = 2y
according to the inscribed angle theorem
OpenStudy (anonymous):
I'm still confused :(
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jimthompson5910 (jim_thompson5910):
say we know that the central angle is 90 degrees, this would make the inscribed angle to be (1/2)*90 = 45 degrees
|dw:1358998093946:dw|
OpenStudy (anonymous):
so "O" in my pic is the inscribed angle?
jimthompson5910 (jim_thompson5910):
no, O is the center of the circle
OpenStudy (unklerhaukus):
mO
jimthompson5910 (jim_thompson5910):
angle NOQ is the central angle
angle NRQ is the inscribed angle
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jimthompson5910 (jim_thompson5910):
angle O is the central angle
jimthompson5910 (jim_thompson5910):
because it's in the center of the circle
jimthompson5910 (jim_thompson5910):
inscribed angle = (1/2)*[ central angle ]
jimthompson5910 (jim_thompson5910):
what is the inscribed angle
jimthompson5910 (jim_thompson5910):
what is the measure of NRQ
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OpenStudy (anonymous):
at the risk of sounding stupid i am not sure at this point
jimthompson5910 (jim_thompson5910):
angle R = angle NRQ
OpenStudy (anonymous):
so 28
jimthompson5910 (jim_thompson5910):
inscribed angle = (1/2)*[ central angle ]
28 = (1/2)*[ central angle ]
find the "central angle"
OpenStudy (anonymous):
56
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