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If one leg of a right triangle is 4 and the second leg is 6, then how long is the hypotenuse?
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((4^2+6^2))^(1/2)
what?
in other words \[\sqrt{4^2+6^2}\]
enter it on a calculator
im not sure if I use the Pythagorean theorem or use 45 45 90?
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x^1/2 = sqrt(x)
just do square root.
and then I get the hypotenuse?
it's pythagorean. you're not given any other angles. yeah
yuuup
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then would I get radical 52?
but simplify it?
mhmm. then simplify that on your calcuator.
look... c^2=a^2+b^2 where c is the hypotenuse, "a" and "b" are the "legs"
I get that.
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so its 2 radical 13.
simplfity that as in decimals...
7.211 units
7.2
yeah
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thank you!!
no problem :)
you're very welcome!
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