A chemistry intern needs 20 liters of a 15% sodium solution. He decided to mix a 10% solution with a 30% solution. How many liters of a 10% solution and a 30% solution does he need.
may I ask how did you set that up please
its wrong
So how is it wrong levinelevine no problem
im solving it, is it 20% in mass or in mole? or it doesnt say?
the question is all I have for in formation
ok, ive got it. here you go
first. we have a 2 equation with 2 variable system. the fist equation can be determined (x+y)=20 where x is the liters of solution 10% and y 30%. then the second equation is 0.1*X+0.3Y=20*0.15. solving this two equation will give the answer. do you know how to do this?
what was ur answer @AIK ? I got 5liter of 30% and 15 of 10%
hold on please
yes
Well clearly the intern is unsophisticated and does not know what he is doing
that is what I got, so I was right after all. Just was not sure since I am pretty tired and did it in my head half dead.
what us .15*20
is*
its the 20 liters of Na multiplied by its concentration in fraction (15%/100)=0.15
Dude levin you are smart
thanx @Barcelona20012 :)
Excuse me Ronaldo Barcelona is clearly better than Real Madrid therefore you may want to change your name
levine i am confused here is what i got so far|dw:1359006925576:dw|
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