Question

vertices of PQR are P(5,-2,-1),Q(1,2,-3) and R(13,6,3). Bisector of angle P meets QR at S.
Find coordinates of S?

Answer 1

angular bisector divides the opposite sides internally in the ratio of the side containing the angle

Answer 2

so first find the length of PQ and PR and then divide QR in the rato of PQ :PR

Answer 3

PQ= 6
PR = 12

Answer 4

@matricked

Answer 5

so find the co-ordinates of a point S which divides QR in the ratio of 6:12 i.e 1:2 internally

Answer 6

x=15/2

Answer 7

y = 20/3
and z =-1
coordinates of S =15/2,20/3,-1

Answer 8

@matricked
am i right

Answer 9

i don't think its the correct cordinate u obtained

Answer 10

Q(1,2,-3) and R(13,6,3)

check if it is (2+13)/3 , (4+6)/3 ,(-6+3)/3--> (15/3),(10/3),-1

Answer 11

oh yes, i thought its 16 , but it was 6

Answer 12

so u got it ..

Answer 13

yes..and of course
thank u so much @matricked

Answer 14

welcome dear