Solve by addition or substitution y=4x-4y 3x+2y=11 Help.
multiply 3x+2y=11 all by -2 and line it up with y=4x-4y. then solve for one variable and then use replacement.
so plug in -2 for x and y and multiply 11 as well by -2?
everything by -2(...)
@Ben103 We already went through a similar question like this. This just contains different numbers.
\[y=4x−4y\qquad\qquad3x+2y=11\] a different method would be to solve the first equation for x (by taking the y terms to the left and dividing by four) then substitute x into the second equation
So far I have (4x-44)-(-6x+-4x)=(-22)-44. Is that good so far?
are you sure you have the question right?
i dont think there are nice solutions to this system
I multiplied -2 by (3x+2y) and 11 and got -6x+-4x=-22
and then lined it up with y=4x-4y
You don't use the elimination method in this one although it still works. YOu use the substitution method because one of the equations has y as the subject which makes your life easier when solving using substitution.
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