Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (theviper):

Linear Equations in Two Variables question :) Please help :)

OpenStudy (hba):

Well there are a few methods we can use, 1)Breaking the middle term 2)Completing the whole square 3)Quad formula.

OpenStudy (hba):

Do you have a particular question i can help you on ?

OpenStudy (theviper):

A motorboat whose speed is \(\large{18km/hr}\) in still takes one hour more to go \(24km\) upstream than to return downstream the same spot. Find the speed of the stream.

OpenStudy (shubhamsrg):

Did you form your equations ?

OpenStudy (theviper):

that is the problem :D

OpenStudy (theviper):

i know how to solve them but can't make those equations :(

OpenStudy (shubhamsrg):

Leme try : Let speed of stream be x distance = 24 for upstream, speed = 18-x for downstream , speed = 18+x If time taken to go downstream is t, then it says time taken to go upstream is (t-1) Use distance = speed/time to get your 2 eqns. hope this helps ?

OpenStudy (shubhamsrg):

Am sorry, if t is for downstream, then (t+1) is for upstream*

OpenStudy (theviper):

\[\LARGE{\dfrac{24}{18-x}=t+1}\quad\quad\quad..............(eq.i)\] \[\LARGE{\dfrac{24}{18+x}=t-1}\quad\quad\quad..............(eq.ii)\] ????????

OpenStudy (theviper):

Am i right @hartnn ??

hartnn (hartnn):

those are correct equations.

OpenStudy (theviper):

thanx everyone :)

hartnn (hartnn):

wait, why is there t+1 ? what have you considered 't' as ?

OpenStudy (theviper):

time

hartnn (hartnn):

t= downstream time ?? or t= upstream time ?

OpenStudy (theviper):

oh wait @shubhamsrg is wrong i think :/

OpenStudy (theviper):

he took t+1 as upstream time & t-1 as downstream instead of taking t as downstream time & t+1 as upstream time :)

hartnn (hartnn):

no...he didn't take t+1 as upstream time & t-1 as downstream... he said "\( \large If\) time taken to go downstream is t, then it says time taken to go upstream is (t-1)" actually its t+1.

hartnn (hartnn):

as you said....so what are your modified equations ?

OpenStudy (theviper):

\[\LARGE{\dfrac{24}{18-x}=t-1}\quad\quad\quad..............(eq.i)\]\[\LARGE{\dfrac{24}{18+x}=t}\quad\quad\quad..............(eq.ii)\]

hartnn (hartnn):

if downstream = t, upstream = t+1 .

OpenStudy (theviper):

oh yes sorry :)

OpenStudy (shubhamsrg):

I had corrected myself after that! :|

OpenStudy (theviper):

yess:/

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!