Linear Equations in Two Variables question :) Please help :)
Well there are a few methods we can use, 1)Breaking the middle term 2)Completing the whole square 3)Quad formula.
Do you have a particular question i can help you on ?
A motorboat whose speed is \(\large{18km/hr}\) in still takes one hour more to go \(24km\) upstream than to return downstream the same spot. Find the speed of the stream.
Did you form your equations ?
that is the problem :D
i know how to solve them but can't make those equations :(
Leme try : Let speed of stream be x distance = 24 for upstream, speed = 18-x for downstream , speed = 18+x If time taken to go downstream is t, then it says time taken to go upstream is (t-1) Use distance = speed/time to get your 2 eqns. hope this helps ?
Am sorry, if t is for downstream, then (t+1) is for upstream*
\[\LARGE{\dfrac{24}{18-x}=t+1}\quad\quad\quad..............(eq.i)\] \[\LARGE{\dfrac{24}{18+x}=t-1}\quad\quad\quad..............(eq.ii)\] ????????
Am i right @hartnn ??
those are correct equations.
thanx everyone :)
wait, why is there t+1 ? what have you considered 't' as ?
time
t= downstream time ?? or t= upstream time ?
oh wait @shubhamsrg is wrong i think :/
he took t+1 as upstream time & t-1 as downstream instead of taking t as downstream time & t+1 as upstream time :)
no...he didn't take t+1 as upstream time & t-1 as downstream... he said "\( \large If\) time taken to go downstream is t, then it says time taken to go upstream is (t-1)" actually its t+1.
as you said....so what are your modified equations ?
\[\LARGE{\dfrac{24}{18-x}=t-1}\quad\quad\quad..............(eq.i)\]\[\LARGE{\dfrac{24}{18+x}=t}\quad\quad\quad..............(eq.ii)\]
if downstream = t, upstream = t+1 .
oh yes sorry :)
I had corrected myself after that! :|
yess:/
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